0=10x^2+10x+13

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Solution for 0=10x^2+10x+13 equation:



0=10x^2+10x+13
We move all terms to the left:
0-(10x^2+10x+13)=0
We add all the numbers together, and all the variables
-(10x^2+10x+13)=0
We get rid of parentheses
-10x^2-10x-13=0
a = -10; b = -10; c = -13;
Δ = b2-4ac
Δ = -102-4·(-10)·(-13)
Δ = -420
Delta is less than zero, so there is no solution for the equation

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